| 4:35:49 AM PDT - Fri, Jun 8th 2018 |
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Multiplicity is 2S+1
First scenario:
Fragment 1; charge = -1, multiplicity = -10 so 9 unpaired beta electrons [2(9/2)+1 = 10]
Fragment 2; charge = -1, multiplicity = 10 so 9 unpaired alpha electrons [2(9/2)+1 = 10]
Total should then be charge = -2 and multiplicity = 1 since we have even number of alpha and beta electrons [2(0/2)+1 = 1]
You specified charge = -2 and multiplicity = 1 for the total, so the calculation works
Second scenario:
Fragment 1, -1 charge, multiplicity = 8 so 7 unpaired alpha electrons [2(7/2)+1 = 8]
Fragment 2, -1 charge, multiplicity = 10 so 9 unpaired alpha electrons [2(9/2)+1 = 10]
Total should then be -2 charge and multiplicity = 17 since we have 16 unpaired alpha electrons [2(16/2)+1 = 17]
You specified charge = -2 and multiplicity = 1 for the total, so the calculation fails
(Even if you had a typo in your post and meant to write multiplicity = -8 for the first fragment, the total would still not be multiplicity = 1 since you would have two more alpha electrons than beta electrons, [2(2/2)+1 = 3])
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